Answer:
Given -
- Initial velocity of the ball, u = 0 m/s
- final velocity of the ball, v = 12 m/s
- Time taken = 36 sec
[tex] \\ [/tex]
To find -
- Acceleration of the ball.
[tex] \\ [/tex]
Solution -
[tex] \\ \sf \: A = \frac{v - u}{t} \\ \\ \\ \implies \sf \: A = \frac{12 - 0}{36} \\ \\ \\ \implies \sf \: A = \frac{12}{36} \\ \\ \\ \implies \sf \underline{A = 0.33 \: m \: / {s}^{2} } \\ [/tex]
Therefore, the acceleration of the ball is 0.33 m/s².
