Answer:
the new volume is 1.35L
Explanation:
The computation of the new volume in the case when the temperature rises to 45 degrees is shown below:
GIven that
Volume = 1.25L
And, the temperature is 22 degrees celsius
So, [tex]T_1[/tex] = (275 + 22)k
= 297 k
Now
[tex]T_2[/tex] = (275 + 45)k
= 320 k
Now as it is a constant pressure
So, the new volume is
[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\\V_2 = \frac{V_1}{T_1}\times T_2 \\\\= \frac{1.25}{297}\times 320[/tex]
= 1.35L
hence, the new volume is 1.35L
