davinbrown1 davinbrown1

09-09-2020
Mathematics

contestada

How many solutions exist for the given equation? 12x + 1 = 3(4x + 1) – 2

Respuesta :

09-09-2020

Answer:

3=3 infinity many solutions

Step-by-step explanation:

12x+1=3(4x+1)-1

3x4x 3x1

12x+1=12x+3-2

+2 +2

12x+3=12x+3

-12x -12x

3=3

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