Answer:
The magnitude of vector ab |M| = √26
Step-by-step explanation:
Mathematically, the magnitude of the position vectors is the distance between the two position vectors.
So in this case;
|M| = √{(x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2}
From the question;
(x1,y1,z1) = (2,-1,4)
(x2,y2,z2) = (1,3,1)
Substituting these values, we have
M = √(1-2)^2 + (3-(-1))^2 +(1-4)^2
M = √(1 + 16 + 9
M = √26
