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  • 08-08-2020
  • Mathematics
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HELPP ASAP MATH
The points -3,2 and -2,3 lie on a circle whose center is on the x-axis. What is the radius of the circle?

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zubam2002
zubam2002 zubam2002
  • 09-08-2020

Answer:

0.7

Step-by-step explanation:

The coordinates of the midpoint between (-3,2) and (-2,3) is:

(--5/2,5/2)

The equation of the circle of centre (-5/2,5/2) passing through (-3,2) , using the formula r²= (x -a)² + (y - b)² is as follow:

r² = (-3 + 5/2)² + (2 - 5/2)²

r² = (-1/2)² + (--1/2)² = 1/4 + 1/4

r = √(1/2) = 1/1.414 = 0.7

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