dzeller808
dzeller808 dzeller808
  • 08-08-2020
  • Mathematics
contestada

SP=2x+3, and LN=5x−14. Find SP. A. 20 B. 86 C. 43 D. 50

SP2x3 and LN5x14 Find SP A 20 B 86 C 43 D 50 class=

Respuesta :

jimrgrant1 jimrgrant1
  • 08-08-2020

Answer:

C

Step-by-step explanation:

A segment joining the midpoints of two sides of a triangle is half the length of the third side.

SP is a midline segment, thus

SP = [tex]\frac{1}{2}[/tex] LN , that is

2x + 3 = [tex]\frac{1}{2}[/tex] (5x - 14) ← multiply both sides by 2

4x + 6 = 5x - 14 ( subtract 4x from both sides )

6 = x - 14 ( add 14 to both sides )

20 = x

Thus

SP = 2x + 3 = 2(20) + 3 = 40 + 3 = 43 → C

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