mgiu0avbrown
mgiu0avbrown
06-09-2016
Mathematics
contestada
solve a=2pir^2 2pirh for pi
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gibrancn
gibrancn
06-09-2016
a = 2[tex] \pi [/tex] [tex] r^{2} [/tex] 2[tex] \pi [/tex]rh
|Divide by 4h
[tex] r^{3} [/tex]
[tex] \pi ^{2} [/tex] = [tex] \frac{a}{4h r^{3} } [/tex]
|Square root on both sides
[tex] \pi [/tex] = [tex] \sqrt{ \frac{a}{4h r^{3} } } [/tex]
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