Answer:
[tex]solubility=0.25mol/dm^3[/tex]
Explanation:
number of moles of solute=0.03mol
volume of solution in dm³=1.2dm³
solubility=?
as we know that
[tex]solubility=\frac{number of moles of solute}{volume of solution indm}[/tex]
[tex]solubility=\frac{0.03mol}{1.2dm^3}[/tex]
[tex]solubility=0.25mol/dm^3[/tex]
i hope this will help you :)
