apeyderra1323 apeyderra1323
  • 10-06-2020
  • Mathematics
contestada

x=(y+2)^2 solve the equation

Respuesta :

gauravpatwal99 gauravpatwal99
  • 10-06-2020

Answer:

x= y^2+4y+4

Step-by-step explanation:

x= (y+2)(y+2)

x= y^2+2y+2y+4

x= y^2+4y+4

Answer Link
teyake4627
teyake4627 teyake4627
  • 10-06-2020

Answer:

X = y^2 + 4y + 4

Y= (√X) -2

Step-by-step explanation:

X = (Y+2)^2

X = (Y+2)(Y+2)

X = Y^2 + 4y + 4

X = (Y+2)^2

√X = √(Y+2)^2             (taking the root of both sides cancels the exponent)

√X = Y+2

-2        -2

(√X) - 2 = Y

or

Y = (√X) - 2

Answer Link

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