Answer:
The formula is: [tex](x+2)^2+(y-3)^2=25[/tex]
Step-by-step explanation:
Recall the formula for the equation of a circle with center at the point [tex](x_0,y_0)[/tex]of radius "R' as:
[tex](x-x_0)^2+(y-y_0)^2=R^2[/tex]
Therefore for your case, the formula becomes:
[tex](x-x_0)^2+(y-y_0)^2=R^2\\(x-(-2))^2+(y-3)^2=5^2\\(x+2)^2+(y-3)^2=25[/tex]
