Answer:
[tex]0.2y+0.2x-8[/tex]
Step-by-step explanation:
[tex]\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)[/tex]
[tex]=\frac{2}{5}y+\frac{1}{5}x-0.2y-6-2[/tex]
[tex]=\frac{2}{5}y-0.2y+\frac{1}{5}x-6-2[/tex]
[tex]\frac{2}{5}y-0.2y[/tex]
[tex]=y\left(\frac{2}{5}-0.2\right)[/tex]
[tex]\frac{2}{5}-0.2=0.2[/tex]
[tex]=0.2y[/tex]
[tex]=0.2y+\frac{1}{5}x-6-2[/tex]
[tex]\frac{1}{5}x[/tex]
[tex]=\frac{1\cdot \:x}{5}[/tex]
[tex]=\frac{x}{5}[/tex]
[tex]=0.2y+\frac{x}{5}-6-2[/tex]
[tex]=0.2y+0.2x-8[/tex]
