daraeckes daraeckes
  • 06-03-2014
  • Mathematics
contestada

How do I solve 4cos^2 x -1=0

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crisforp
crisforp crisforp
  • 06-03-2014
[tex] (cosx)^{2} = 1/4[/tex] <=> cosx = +1/2 or cosx = -1/2;
cosx = +1/2 => x = +π/3 + 2kπ, where k is an integer or x = -π/3 + 2kπ, where k is an integer;
cosx = -1/2 => x = +2π/3 + 2kπ, where k is an integer or x = -2π/3 + 2kπ, where k is an integer;
Answer Link
chloeholmes chloeholmes
  • 06-02-2020

Answer:

pi/3? 2pi/3?

Step-by-step explanation:

Answer Link

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