Answer:
32.6 Jmol-1
Explanation:
Now we have to use the formula
∆G= ∆H-T∆S where
∆G= change in free energy (the unknown)
∆H= enthalpy change = 91.8KJ
∆S= entropy change= 0.1987 kJ/K
T= temperature= 298K
∆G= 91.8 - (298× 0.1987)
∆G= 91.8 - 59.2126
∆G= 32.6 Jmol-1
