daluzirriyachpadga
daluzirriyachpadga daluzirriyachpadga
  • 07-08-2016
  • Mathematics
contestada

y = sec θ tan θ differentiate

Respuesta :

Hussain514 Hussain514
  • 10-08-2016
Y = sec(θ) tan(θ).
 Solution:
 We use here the product rule that  is 
 (fg) 0 = f 0 g + fg0 .
 So
 y 0 = (sec(θ) tan(θ)) tan(θ) + sec(θ) tan2 (θ)
       = sec(θ)(tan2 (θ) + sec2 (θ)).
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