edgargillan5
edgargillan5 edgargillan5
  • 08-04-2020
  • Mathematics
contestada

Given P(A)=0.33, P(B)=0.6 and P(A∩B)=0.248, find the value of P(A∪B), rounding to the nearest thousandth.

Respuesta :

Ashraf82
Ashraf82 Ashraf82
  • 13-04-2020

Answer:

The value of P(A ∪ B) is 0.682 to the nearest thousandth

Step-by-step explanation:

The addition rule of probability is:

P(A ∪ B) = P(A) + P(B) - P(A ∩ B), where P(A ∪ B) is probability A or B , P(A ∩ B) is probability A and B

∵ P(A) = 0.33

∵ P(B) = 0.6

∵ P(A ∩ B) = 0.248

- Substitute these values in the rule above

∴ P(A ∪ B) = 0.33 + 0.6 - 0.248

∴ P(A ∪ B) = 0.682

The value of P(A ∪ B) is 0.682 to the nearest thousandth

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