Answer:
Step-by-step explanation:
Use the identity [tex]sin(a+b)=sin a cosb+sinbcosa[/tex] where [tex]a=x[/tex] and [tex]b=\pi[/tex].
This results in [tex]sinxcos\pi +sin\pi cosx[/tex]
From the unit circle we know that [tex]cos\pi =-1[/tex] and [tex]sin\pi =0[/tex]
Substitute
[tex]sinx(-1)+(0)cosx[/tex]
Simplify
[tex]-sinx[/tex]
