reganshrader reganshrader
  • 07-04-2020
  • Chemistry
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Given 7.65 mol AgNO3, determine the number of formula units.

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Tringa0 Tringa0
  • 07-04-2020

Answer:

The number of formula units of silver nitrate is [tex]4.61\times 10^{24}[/tex].

Explanation:

Moles of silver nitrate = n = 7.65 mol

1 mole = [tex]N_A=6.022\times 10^{23}[/tex] atoms/ molecules/ ions

Let the number of formula units of silver nitrate be N.

[tex]N=n\times N_A[/tex]

[tex]N=7.65 mol\times 6.022\times 10^{23}=4.61\times 10^{24}[/tex]

The number of formula units of silver nitrate is [tex]4.61\times 10^{24}[/tex].

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