Answer:
[tex]2c^2d\sqrt{7c}[/tex]
Step-by-step explanation:
[tex]\sqrt{28c^5d^2}= \sqrt{2^2.7c^4d^2.c}=2c^2d\sqrt{7c}[/tex]
the answer is b
[tex] \sqrt{7 \times 4 \times c^{4} \times c \times {d}^{2} } \\ 2 {c}^{2} d \sqrt{7c} [/tex]
