brogan2772
brogan2772 brogan2772
  • 09-07-2016
  • Mathematics
contestada

Given that f(x) = x2 + 2x + 3 and g(x) = quantity of x plus four, over three , solve for f(g(x)) when x = 2.

Respuesta :

twvogels
twvogels twvogels
  • 09-07-2016
[tex]f(x)=x^2+2x+3[/tex]
[tex]g(x)=\frac{x+4}{3}[/tex]
[tex]f(g(x))=(\frac{x+4}{3})^2+2(\frac{x+4}{3})+3[/tex]
[tex]f(g(x))=\frac{x^2+8x+16}{9}+\frac{2x+8}{3}+3[/tex]
[tex]f(g(2))=\frac{2^2+8(2)+16}{9}+\frac{2(2)+8}{3}+3[/tex]
[tex]f(g(2))+\frac{4+16+16}{9}+\frac{4+8}{3}+3[/tex]
[tex]f(g(2))=\frac{36}{9}+\frac{12}{3}+3[/tex]
[tex]f(g(2))=4+4+3[/tex]
[tex]f(g(2)=11[/tex]

Check:
g(2)=(2+4)/3=2
f(2)=2^2+2(2)+3=4+4+3=11  Checks. 
Answer Link
Aliwohaish12
Aliwohaish12 Aliwohaish12
  • 09-07-2016
G(2)=(x+4)/3=2 F(2)=x^2+2x+3 4+4+3=11
Answer Link

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