Answer:
Step-by-step explanation:
[tex]6ax^2=(2a)(3x^2)\\\\4ax=(2a)(2x)\\\\10a=(2a)(5)\\\\6ax^2+4ax+10a=(2a)(3x^2)+(2a)(2x)+(2a)(5)\\\\\text{use the distributive property}:\ a(b+c)=ab+ac\\\\=(2a)(3x^2+2x+5)[/tex]
