Answer:
4.21
Explanation:
First, let us generate the dissociation equation. This is illustrated below:
HCl <==> H^+ + Cl^-
From the equation, 1mole of HCl produced 1mole of H^+. This means that 6.2 x 10^-5M will also produce 6.2 x 10^-5M of H^+.
Now we can calculate the pH of the solution as follows:
[H^+] = 6.2 x 10^-5M
pH = —Log [H^+]
PH = —Log 6.2 x 10^-5
pH = 4.21
