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  • 10-02-2020
  • Mathematics
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What are the roots of 27x^3=8

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jdoe0001 jdoe0001
  • 10-02-2020

[tex]\bf 27x^3=8\implies x^3=\cfrac{8}{27}\implies x = \sqrt[3]{\cfrac{8}{27}}\implies x = \sqrt[3]{\cfrac{2^3}{3^3}} \\\\\\ x = \cfrac{\sqrt[3]{2^3}}{\sqrt[3]{3^3}}\implies x=\cfrac{2}{3}[/tex]

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