Respuesta :

[tex]\bf \textit{perimeter of a rectangle}\\\\ P=2(L+h)~~ \begin{cases} L=length\\ h=height\\[-0.5em] \hrulefill\\ P=260\\ L=x \end{cases}\implies 260=2(x+h) \\\\\\ \cfrac{260}{2}=x+h\implies 130=x+h\implies 130-x=h[/tex]