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If an object, beginning at rest, is moving at a speed of 700 m/s after 2.75 min, its rate of acceleration (in m/s 2) is ________. (Assume that the rate of acceleration is constant.)

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abidemiokin

Answer: 4.24m/s²

Explanation:

Acceleration is defined as change in velocity of an object with respect to time. Mathematically,

Acceleration (a) = Change in velocity/time taken

Acceleration (a) = final velocity (v) - initial velocity (u)/time taken (t)

Final velocity = 700m/s

Initial velocity = 0m/s (object beginning from rest)

Time taken = 2.75mins = (2.75 × 60)secs = 165seconds

Substituting the values in the acceleration formula a = v-u/t

a = 700-0/165

a = 4.24m/s²

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