VannahLovesGod VannahLovesGod
  • 07-02-2020
  • Mathematics
contestada

HELP ASAP WILL GIVE BRAINLIEST
Find the oblique asymptote(s).
x^2+x-5/7x^3+4x-2
y=5
y=x
y=7x
y=7
y=2

Respuesta :

sam4040
sam4040 sam4040
  • 14-02-2020

Answer:

[tex]y=7x-7[/tex]

Step-by-step explanation:

Slant asymptote: It is a non-vertical and non-horizontal line graph approaches this line but the graph never crosses it. It exists when degree of numerator is greater than that of denominator. It can be calculated by dividing numerator by denominator.

[tex]Let\ the\ function\ f(x)=\frac{7x^3+4x-2}{x^2+x-5}\\\\Then\ find\ oblique\ asymptote=(x^2+x-5)(7x-7)+(46x-37)\\\\The\ oblique\ asymptote\ (y)=7x-7[/tex]

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