The solution is x = 8 and y = -5
Solution:
Given system of equations are:
x + y = 3 ------ eqn 1
3x + 2y = 14 ------ eqn 2
We have to find the solution to the equations
We can use substitution method to solve
From eqn 1,
x + y = 3
Isolate for "x"
x = 3 - y ------ eqn 3
Substitute eqn 3 in eqn 2
3(3 - y) + 2y = 14
9 - 3y + 2y = 14
-y = 14 - 9
-y = 5
Substitute y = -5 in eqn 3
x = 3 - (-5)
x = 3 + 5 = 8
Thus the solution is x = 8 and y = -5
