akylee2003
akylee2003 akylee2003
  • 09-01-2020
  • Mathematics
contestada

the square root of 12 is the geometric mean between x and y. find x if y = the square root of 3. thanks!!

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jdoe0001 jdoe0001
  • 09-01-2020

[tex]\bf \cfrac{x}{\textit{geometric mean}}=\cfrac{\textit{geometric mean}}{y}\implies \cfrac{x}{\sqrt{12}}=\cfrac{\sqrt{12}}{\sqrt{3}}\implies \cfrac{x}{\sqrt{12}}=\cfrac{\sqrt{4\cdot 3}}{\sqrt{3}} \\\\\\ \cfrac{x}{\sqrt{12}}=\cfrac{\sqrt{4}\sqrt{3}}{\sqrt{3}}\implies \cfrac{x}{\sqrt{12}}=\sqrt{4}\implies \cfrac{x}{\sqrt{12}}=2\implies x = 2\sqrt{12} \\\\\\ x = 2\sqrt{4}\sqrt{3}\implies x=2\cdot 2\sqrt{3}\implies x=4\sqrt{3}[/tex]

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