sammie53 sammie53

10-11-2019
Mathematics

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Given that y = 18 + 3x²
i) express x in terms of y

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11-11-2019

Answer:

[tex]\sqrt{-6 + \frac{y}{3}} = x[/tex]

Step-by-step explanation:

y = 18 + 3x²

- 18 - 18

__________

[tex]\frac{-18 + y}{3} = \frac{3x^2}{3} \\ \\ -6 + \frac{y}{3} = x^2 \\ \\ \sqrt{-6 + \frac{y}{3}} = x[/tex]

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