Answer:
n = 0.112 mol
Explanation:
Given data:
Volume of gas = 2.50 L
Temperature = 273 K
Pressure = 1 atm
Moles of gas = ?
Solution:
PV = nRT
n = PV/RT
n = 1 atm× 2.50 L / 0.0821 atm. L. K⁻¹.mol⁻¹ . 273 K
n = 2.5 atm. L /22.4 atm. L. mol⁻¹
n = 0.112 mol
