Answer:
Volume of gold coin will be [tex]4.792\times 10^{-7}m^3[/tex]
Explanation:
We have given mass of the gold coin m = 9.25 gram = [tex]9.25\times 10^{-3}kg[/tex]
Density of gold is given as d = [tex]=19300kg/m^3[/tex]
We know that density [tex]=\frac{mass}{volume}[/tex]
So volume [tex]=\frac{mass}{density}=\frac{9.25\times 10^{-3}}{19300}=4.792\times 10^{-7}m^3[/tex]
So volume of gold coin will be [tex]4.792\times 10^{-7}m^3[/tex]
