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08-08-2019
Chemistry

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At a certain temperature, the solubility of zinc(I) chromate is (7.0x10^-5) M. What is the Ksp?

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gbustamantegarcia054 gbustamantegarcia054

16-08-2019

Answer:

Ksp = 4.9 E-9

Explanation:

S = 7.0 E-5 M

ZrCrO4 ↔ Zr²+ + CrO4²-

solubility: S S S

⇒ Ksp = [ Zr²+ ] * [ CrO4²- ]

⇒ Ksp = S * S = S²

⇒ Ksp = ( 7.0E-5)²

⇒ Ksp = 4.9E-9

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