Answer:
=3x+27y−6
Step-by-step explanation:
3(3x−(2−6y+2x)+3y)
=(3)(3x+−2+6y+−2x+3y)
=(3)(3x)+(3)(−2)+(3)(6y)+(3)(−2x)+(3)(3y)
=9x−6+18y−6x+9y
