mrspitts327 mrspitts327

08-05-2019
Mathematics

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Find the number of real number solutions for the equation. x^2+0x-1=0

Respuesta :

absor201 absor201

10-05-2019

Answer:

+1

-1

Step-by-step explanation:

Given equation :

[tex]x^{2} +0x-1[/tex] = 0

[tex]x^{2} -1 = 0\\x^{2} =1\\x=\sqrt{1}[/tex]

x= ±1

x= 1 and x= -1

±1 lies in solution set of real numbers !

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