Step-by-step explanation:
[tex]10x^2-5x+11=9x^2+x+83\qquad\text{subtract}\ 9x^2\ \text{and}\ x\ \text{and}\ 83\\\\(10x^2-9x^2)+(-5x-x)+(11-83)=0\\\\x^2-6x-72=0\\\\x^2+6x-12x-72=0\\\\x(x+6)-12(x+6)=0\\\\(x+6)(x-12)=0[/tex]
[tex]\text{The zeros:}\\\\x+6=0\qquad\text{subtract 6 from both sides}\\\boxed{x=6}\\\\x-12=0\qquad\text{add 12 to both sides}\\\boxed{x=12}[/tex]
