dylanramsey dylanramsey

07-05-2019
Physics

contestada

A 2-kg bowling ball rolls at a speed of 10m/s on the ground whats its ke

Respuesta :

jcherry99 jcherry99

17-05-2019

Answer:

Explanation:

I wonder what level of physics you are taking? If this is a beginning course (which I'm going to assume) then the KE is

KE = 1/2 m v^2

KE = 1/2 * 2kg * (10 m/s)^2

KE = 100 Joules.

If you are in an upper level course and need to take into account the rotational motion, leave a note.

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