MNBASKETBALL1020 MNBASKETBALL1020
  • 08-04-2019
  • Chemistry
contestada

Determine the celsius temperature of 2.49 mol of gas contained in a 1.00 l vessel

Respuesta :

jamuuj jamuuj
  • 18-04-2019

Answer:

= -266.24°C

Explanation:

According to ideal gas law;

PV = nRT, where P is pressure, V is the volume, n is the number of moles, R is the ideal gas constant and T is the temperature.

PV = nRT  

T = PV/(nR)

   = 143 kPa * (1atm/101.325 kPa) * 1.00L / (2.49 mol * 0.08206 Latm/molK)

    = 6.91 K

     = -266.24°C

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