Respuesta :

Given that  

Amount of sugar = 6 g

Volume of water = 74 ml or 0.074 L

Number of moles of sugar = amount in g  / molar mass

= 6 g/ 342.3 g/mol

=0.018 moles  

Therefore molarity or concentration = 0.018 mole / 0.074 L

= 0.24 M


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