Answer:
The answer is the option D
[tex]x\leq 7/13[/tex]
Step-by-step explanation:
we have
[tex]-\frac{6}{5}(4-x)\leq -4(x+\frac{1}{2})[/tex]
Multiply by [tex]-5[/tex] both sides
[tex]6(4-x)\geq 20(x+0.5)\\24-6x\geq20x+10\\24-10\geq 20x+6x\\14\geq 26x[/tex]
Rewrite
[tex]26x\leq 14\\x\leq 14/26\\ x\leq 7/13[/tex]
