h2spdobooHenr
h2spdobooHenr h2spdobooHenr
  • 08-04-2016
  • Chemistry
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A compound was isolated and found to contain 72.2% magnesium and the rest nitrogen. What is the empirical formula of this compound?

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ojuelagba ojuelagba
  • 09-04-2016
Since the compound is 72.2% Mg then there would be 27.8% N. Then you can just change it to 72.2 g Mg and 27.8 g N.
then convert to moles by dividing by molecular mass.
72.2÷24.31=2.96 moles Mg
27.8÷14.01=1.98 moles N
then divided by the lowest number.
2.96÷1.98=1.5
Since it is 1.5 you multiply by 2. so you have 3 Mg
1.98÷1.98=1 N
so the empirical formula is Mg3N
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