Respuesta :

RedRicin
continuing from previous post:

1. supplementary
28 + x = 180
subtract 28 from each side
x = 152°
m<FEG = 152°
(they're the same thing, since <FEG is marked x)

2. complementary
74 + x = 90
x = 16°
m<KIL = 16°

3. vertical
135 = 5x
divide each side by 5
x = 27°

supplementary
135 + O = 180
O = 45°

4. complementary
x + x = 90
2x = 90
x = 45°
<RUS = 45°
<TUS = 45°

5. vertical
<AED = 72°

72 = 2x - 6
78 = 2x
39 = x

6. supplementary
2x + 2x = 180
4x = 180
x = 45°
<FIH = 45°
<HIG = 45°

7. complementary
x + 2x = 90
3x = 90
x = 30°
<AOB = 30°
<BOC = 60°

8. < YOZ is a right angle, so <YOZ = 90°

< WOX is complementary to the 40° angle.
< WOX + 40 = 90
< WOX = 50°

< XOZ can be found by adding together the 40° and < YOZ.
40 + 90 = < XOZ = 130°
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