meghanrhughes meghanrhughes

07-12-2018
Mathematics

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find 4i(3-2i) in standard form

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wegnerkolmp2741o wegnerkolmp2741o

07-12-2018

Answer:

8+12i

Step-by-step explanation:

4i(3-2i)

distribute

4i*3 - 4i* 2i

12 i - 8i^2

remember i^2 = -1

12i - 8(-1)

12i +8

in the form a+bi

8+12i

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