opalvictoria04 opalvictoria04
  • 06-12-2018
  • Mathematics
contestada

In an arithmetic sequence {an}, if a1 = 5 and d = 3, find a72. A) 216 B) 218 C) 221 D) 223

Respuesta :

LammettHash
LammettHash LammettHash
  • 07-12-2018

The arithmetic sequence with the given condition is determined recursively by

[tex]\begin{cases}a_1=5\\a_n=a_{n-1}+3&\text{for }n>1\end{cases}[/tex]

So we have

[tex]a_2=a_1+3[/tex]

[tex]a_3=a_2+3=a_1+3(2)[/tex]

[tex]a_4=a_3+3=a_1+3(3)[/tex]

and so on with the general pattern

[tex]a_n=a_1+3(n-1)[/tex]

This means the 72nd term in the sequence is

[tex]a_{72}=a_1+3(72-1)=5+3(71)=218[/tex]

so the answer is B.

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