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08-10-2018
Chemistry

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how many grams of oxygen is needed to completelt react with of 9.30 of aluminum

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ilzinhootigee ilzinhootigee

08-10-2018

Hey there!

Given the reaction:

4 AI + 3O2 ------> 2 AI2O3

4 moles Al --------- 3 moles O2

9.30 moles Al --------- ?? moles O2

9.30 * 3 / 4 => 6.975 moles of O2

Molar mass O2 => 32.0 g

Therefore:

6.975 * 32.0 => 223.3 g of Oxygen

Hope that helps!

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