[tex]\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ V=972\pi \end{cases}\implies 972\pi =\cfrac{4\pi r^3}{3}\implies (3)972\pi =4\pi r^3 \\\\\\ \cfrac{(3)972\pi }{4\pi }=r^3\implies 729=r^3\implies \sqrt[3]{729}=r\implies 9=r[/tex]
Answer:
9 ft
Step-by-step explanation:
Verified correct with test results.
