keke7949 keke7949
  • 07-09-2018
  • Mathematics
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How do I solve this

How do I solve this class=

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gmany
gmany gmany
  • 08-09-2018

[tex]sine=\dfrac{opposite}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}[/tex]

[tex]\sin B=\dfrac{b}{a};\ \tan C=\dfrac{c}{b}\\\\\sin B\cdot\tan C=\dfrac{b}{a}\cdot\dfrac{c}{b}=\dfrac{c}{a}\\\\\sin C=\dfrac{c}{a};\ \tan B=\dfrac{b}{c}\\\\\sin C\cdot\tan B=\dfrac{c}{a}\cdot\dfrac{b}{c}=\dfrac{b}{a}[/tex]

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