loganmichaelajp3ea4n loganmichaelajp3ea4n
  • 11-08-2018
  • Mathematics
contestada

The second term of the expansion (3x-4y)^5 is

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bawbdmo
bawbdmo bawbdmo
  • 11-08-2018

To solve this, we're going to have to use the binomial theorem. It states that:

[tex] (x+y)^{n}=\sum_{k=0}^{n} \binom{n}{k}x^{n-k}y^k [/tex]

If you want a specific term, we can just disregard the polynomial and use this:

[tex] A_k= \binom{n}{k-1}x^{n-k-1}y^{k-1} [/tex]

Where A_k is the kth term. In the context of this problem it would look like:

[tex] A_2= \binom{5}{1}(3x)^{5-1}(-4y)^1= 5*81*-4*x^4*y=1620x^4y [/tex]

So, based on that, our second term is [tex] 1620x^4y [/tex]

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