To solve this problem, you can use a trick that holds true for every possible triplet of consecutive integers: their sum is always three times the middle number.
In fact, if you call the middle number [tex] x [/tex], the three consecutive numbers are [tex] x-1,\ x,\ x+1 [/tex] and their sum is [tex] (x-1)+x+(x+1) = x+x+x-1+1 = 3x [/tex]
So, since [tex] \frac{267}{3} = 89 [/tex], the middle number is 89. So, the three numbers are 88, 89, 90.
