Respuesta :

707863128
The answer will be .04[tex] x^{2} [/tex] -0.2xy+0.25[tex] y^{2} [/tex] 

using the formula  [tex] a^{2} -2ab + b^{2} [/tex]
apologiabiology
I thnk you means exand

so
(0.2x-0.5y)^2=(0.2x-0.5y)(0.2x-0.5y)

use distributive prpoety
a(b+c)=ab+ac
so
(0.2x-0.5y)(0.2x-0.5y)=(0.2x-0.5y)(0.2x)+(0.2x-0.5y)(-0.5y)=(0.2x)(0.2x)+(-0.5y)(0.2x)+(0.2x)(-0.5y)+(-0.5y)(-0.5y)=0.4x^2-0.2xy+0.25y^2



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