The equation for a circle in standard form is [tex](x-h)^2+(y-k)^2=r^2[/tex], where h and k are the coordinates of the center. Our center has an h value of -2 and a k value of -3 with an r value of 3. Fitting those values into our standard form of a circle we have [tex](x-(-2))^2+(y-(-3))^2=3^2[/tex]. Subtracting a negative is the same as adding, and squaring the right side gives us 9, so the equation is [tex](x+2)^2+(y+3)^2=9[/tex]. Third choice from the top.
