aleixsbriggs231 aleixsbriggs231
  • 11-05-2018
  • Mathematics
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What is the y-intercept of the equation of the line that is perpendicular to the line y = 3/5x + 10 and passes through the point (15, –5)?

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sqdancefan
sqdancefan sqdancefan
  • 16-05-2018
The slope of the perpendicular line is the negative reciprocal of that of the given line, so is
  -1/(3/5) = -5/3
Then the point-slope equation of the perpendicular line can be written as
  y = (-5/3)(x -15) -5
  y = (-5/3)x +20

The y-intercept of the perpendicular line is y=20.
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